I have provided accounts of five striking coincidences over my lifetime. The five events individually have odds in the range 10^{-9 }to 10^{-18}. What are the odds that all five coincidences could happen to one individual?

To determine the probability of five independent events, A, B, C, D and E, all occurring, we need to multiply the probabilities of the individual events:

**P****(****A ****a****n****d ****B and C and D and E****) = ****P****(****A****)****×****P****(****B****) x ****P****(C****)****×****P****(D****) ****x**** P(E) **

The five coincidences, which were independent of each another, are as follows:

**A) The Chiswick Coincidence: P=10 ^{-18 }= one chance in 1,000,000,000,000,000,000 = one in one quintillion (a million, million, million)**

**B) Coincidence or Luck?:** **P = 10 ^{-10 } = one chance in ten billion.**

**C) Citizen 63 – Marion Knight: P= 4.5 x 10 ^{-10 } = 4.5 chances in ten billion**

**D) The Flying Horseshoe: P = 1.3 x 10 ^{-12} = 1.3 chances in a million, million**

**E) Under the Wallpaper: P = 5.08 x 10 ^{-9} = 5 chances in a billion**

The combined probability of the five events is :

**P = 10 ^{-18} x 10^{-10} x 4.5 x 10^{-10} x 1.3 x 10^{-12 }x 5.08 x 10^{-9}**

**P = 3 x 10**^{-58 }

*This is one of the smallest probabilities imaginable. *

*Yet, according to the accepted scientific theory, coincidences are chance events, and so there is nothing extraordinary here. *